Stoichiometry Solutions

Practice Problems Sheet

To view the practice problems, click on the link above.

!Solutions!

Below are the problems' solutions. If you have any questions, simply post a comment and I'll try to answer them as soon as possible. Click on the images to zoom in.

**Pay attention to significant figures. If the problem starts with three, then the final answer can only have three. This might require rounding.**

1) look at photo.
2) 125gFeCl3 -->  124g NH4Cl,  127gNH4OH --> 194gNH4Cl FeCl3 is the limiting reactant
3) There are 45.9g NH4OH left over.
4) 44.4% yield

1) Look at photo
2) 12.5mol CuNO3 --> 1.12 x 10^3g Fe(NO3)2, 9.50 x 10^28 molecules Fe --> 2.80 x 10^7g Fe(NO3)2

CuNO3 is the limiting reactant

3) 8.7 x 10^6g Fe(NO3)2
4)88% yield

1) Look at photo
2)125mol Al --> 6370g Al2O3, unlimited O2 --> ∞Al2O3  Al is the limiting reactant
3)O2 is unlimited so the amount left over is unlimited
4)100%

 

1) Look at photo

2)125gAl --> 14.0g H2, 129ml H2SO4 --> .521gH2  H2SO4 is the limiting reactant

3)120g Al are left over after the reaction