Sunday, April 24, 2011

Pre Test Tutoring

For anyone who wants to take advantage of it, I will be at the school at 7:30 Monday morning. If the door is locked, I will leave a note telling you which room to go to. Have questions ready since we might not have much time to review the material.

Hope to see some of you guys there!

Saturday, April 23, 2011

Stoichiometry Solutions


To view the practice problems, click on the link above.


!Solutions!
Below are the problems' solutions. If you have any questions, simply post a comment and I'll try to answer them as soon as possible. Click on the images to zoom in.

**Pay attention to significant figures. If the problem starts with three, then the final answer can only have three. This might require rounding.**

1) look at photo.
2) 125gFeCl3 -->  124g NH4Cl,  127gNH4OH --> 194gNH4Cl FeCl3 is the limiting reactant
3) There are 45.9g NH4OH left over.
4) 44.4% yield


1) Look at photo
2) 12.5mol CuNO3 --> 1.12 x 10^3g Fe(NO3)2, 9.50 x 10^28 molecules Fe --> 2.80 x 10^7g Fe(NO3)2
CuNO3 is the limiting reactant
3) 8.7 x 10^6g Fe(NO3)2
4)88% yield




1) Look at photo
2)125mol Al --> 6370g Al2O3, unlimited O2 --> ∞Al2O3  Al is the limiting reactant
3)O2 is unlimited so the amount left over is unlimited
4)100%



1) Look at photo
2)125gAl --> 14.0g H2, 129ml H2SO4 --> .521gH2  H2SO4 is the limiting reactant
3)120g Al are left over after the reaction